9y^2+10y+1=0

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Solution for 9y^2+10y+1=0 equation: 



9y^2+10y+1=0

a = 9; b = 10; c = +1;
Δ = b2-4ac
Δ = 102-4·9·1
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$


$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-8}{2*9}=\frac{-18}{18}
=-1
$


$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+8}{2*9}=\frac{-2}{18}
=-1/9
$

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